Monday, 14 October 2013

12. Theoretical and excess air
If two reactants are needed for a reaction the less expensive reactant is fed into system at excess to convert the total of the expensive reactant. An example of an inexpensive reactant can be air, which is free. Combustion reactions are run with more air than is needed to supply oxygen in the right proportion to the fuel.

Theoretical Oxygen:  Moles(batch process) or molar flow rate(continues process) of Oxygen is needed for complete combustion of all fuel that is fed to the reactor. It could be assumed that all carbon in the fuel can be oxidized to CO and hydrogen to H₂O.

Theoretical air: Theoretical oxygen quantity that is contained in the air.

Excess Air: Theoretical air amount that is exceeded by the amount of air fed
Percent Excess air Formula: [(moles air)fed – (Moles air)theoretical / (moles air) theoretical] x 100%

It is useful to know the fuel feed rate and stoichiometry in the equations to help with calculations like theoretical O₂ and air feed rates. If the actual feed rate of air is known it is possible to calculate percent excess air.


13. Material Balances on Combustion Reactors
Solving material balances for combustion reactors is the same as for any reactive system but have a few points to keep in mind like:
1.       After drawing flow chart your outlet stream must contain
i)        Unreacted fuel(unless told otherwise)
ii)       Unreacted oxygen
iii)     Water and carbon dioxide(also carbon monoxide if said is present by problem)
iv)     Nitrogen since air is not pure

2.       Calculate oxygen feed rate from the specified percent oxygen or percent excess air. Calculate theoretical O from fuel feed rate and the reaction stoichiometry for complete combustion then calculate oxygen feed rate by multiplying the theoretical oxygen

3.       If one reaction is involved then the three methods of balancing (molecular, atomic and extent of reaction) are equal. If several reactions occur at the same tome atomic species are more convenient.

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Some additional Considerations about chemical processes (what you do not learn out of textbooks)
1.       Processes do not always work as designed
2.       Variables measured to precision in field measurements have errors
3.       Humans make mistakes that influence the process outcome
4.       You will not always have all the data you need and may have to make assumptions
5.       In textbooks material balances have a closure of 100%, in practice there is no such thing as a true steady state
6.       Textbooks have only one correct answer whilst real problems may have the possibility where you can find a variety of solutions.
  

Reasons for differences between design values and experimental values:
1.       Human errors and data scatter
2.       Impurities in feed
3.       Incorrect assumptions of steady state
4.       Incorrect assumptions that MEK is not reactive.
5.       Errors due to approximation in the experimental data analysis
6.       Approximations in the design analysis





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